Question

sendo y=-2/3x + 18, calcule y quando:a) x=27. c)x=0b) x=-3. d)x=-6

Answer 1

$y=-\dfrac{2}{3}x+18$

a) $x=27$

$y=-\dfrac{2}{3}\cdot27+18=-\dfrac{54}{3}+18=-18+18 \iff \boxed{y=0}$

b) $x=-3$

$y=-\dfrac{2}{3}\cdot(-3)+18=\dfrac{6}{3}+18=2+18 \iff \boxed{y=20}$

c) $x=0$

$y=-\dfrac{2}{3}\cdot0+18=0+18 \iff \boxed{y=18}$

d) $x=-6$

$y=-\dfrac{2}{3}\cdot(-6)+18=\dfrac{12}{3}+18=4+18 \iff \boxed{y=22}$