Question

Sendo (x+y) = 256 e x²+y=130 determine xy

Answer 1

Resposta:

Explicação passo-a-passo:

$x+y = 256\\x^2 + y^2 = 130$

$(x+y)^2 = 256^2\\x^2 +2xy+y^2 = 256^2\\x^2 +y^2 +2xy = 256^2\\130+2xy =256^2\\2xy = 65 536-130\\2xy = 65 406\\xy=\frac{65 406}{2}\\xy = 32 703$