Question

Sendo
x = [(-6)^2-(-2)^3]÷(-4) e
y = (-6)^2÷(-3)^2-1^6, determine o valor de x+y

Answer 1

vamos resolver.


x = [(-6)^2-(-2)^3]÷(-4)
x = [ 36 -8 ] ÷ (4)
x = 28÷4
x = 7

y = (-6)^2÷(-3)^2-1^6
y = 36 ÷ 9 - 1
y = 4 -1
y = 3

→ x + y = 7 + 3
x + y = 10

att Jhonny ♥