Question

sendo x = π/4, determine o valor de p, sendo:​

Answer 1

$\text{P} = 2 \: \text{sen} \: x + \cos x - 2 \: \text{sen} \: x + 2 \cos x \\ \text{P} = 2 \: \text{sen} \: \dfrac{\pi}{4} + \cos \dfrac{\pi}{4} - 2 \: \text{sen} \: \dfrac{\pi}{4} + 2 \cos \dfrac{\pi}{4} \\ \text{P} = 2 \bigg( \dfrac{ \sqrt{2} }{2} \bigg) + \dfrac{ \sqrt{2} }{2} - 2 \bigg( \dfrac{ \sqrt{2} }{2} \bigg) + 2 \bigg(\dfrac{ \sqrt{2} }{2} \bigg) \\ \text{P} = \dfrac{ \sqrt{4}}{2} + \dfrac{ \sqrt{2} }{2} - \dfrac{ \sqrt{4} }{2} + \dfrac{ \sqrt{4} }{2} \\ \text{P} = \dfrac{ \not{2}}{ \not{2}} + \dfrac{ \sqrt{2} }{2} - \dfrac{ \not{2}}{ \not{2}} + \dfrac{ \not{2}}{ \not{2}} \\ \text{P} = 1 + \frac{ \sqrt{2} }{2} - 1 + 1 \\ \text{P} = 1 \frac{ \sqrt{2} }{2}$