Matemática, perguntado por Sarah1607200, 1 ano atrás

Sendo x= 4,123. 10 elevado a 19 e y=4,012 .10 elevado a 15, calcule x+y e x-y.

Soluções para a tarefa

Respondido por hcsmalves
66
x=4,123.10^1^9 \\ y=4,012.10^1^5 \\ x+y=10^1^5(4,012 +4,123.10^4)=(4,012+41230).10^1^5= \\ 41234,012.10^1^5=4,1234012.10^-^4.10^1^5=4,1234012.10^1^1 \\ x-y=4,123.10^1^9-4,012.10^15=10^1^5(4,123.10^4-4,012)= \\ 10^1^5(41230-4,012)=41225,988.10^1^5=4,1225.10.10^-4.10^1^5= \\ 4,1225988.10^1^1

Sarah1607200: muito obrigada!!!!
hcsmalves: Disponha
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