Question

sendo x=(2²)³,y=(2³)²e z=2³²calcule x·y·z na forma de potencia

Answer 1

$x=(2^2)^3=2^6 \\ \\ y=(2^3)^2=2^6 \\ \\ z= 2^{3^2} =2^9 \\ \\ x.y.z= \\ \\ 2^6.2^6.2^9=2^{6+6+9}=2^{21}$