Question

Sendo W=3a2+a+2 ,K=2a2-a-2 e y=5a2+7 calcule: a)w+k= b)k+y= c)w+k+y= d)w+y=

Answer 1

a)w+k= 3a2+a+2 + 2a2-a-2+5a2+7 = 10a^2 + 7

b)k+y= 2a2-a-2+5a2+7 = 7a^2 - a + 5

c)w+k+y= 3a2+a+2+2a2-a-2+5a2+7 = 10a^2 + 10

d)w+y= 3a2+a+2+5a2+7 = 8a^2 + a + 9

c)w+k+y= 3a2+a+2+2a2-a-2+5a2+7 = 
c)w+k+y= 3a2+a+2+2a2-a-2+5a2+7 =