Question

sendo U = R resolva as equancoes esponenciais

Me ajudem pfvr​

Answer 1

Resposta:

Explicação passo-a-passo:

3^x=81

3^x=3^4

x=4

5^x-125=0

5^x=0+125

5^x=125

5^x=5^3

x=3

(2/5)^x=125/8

(2/5)^x=(5/2)^3

x=3

V3=27^x

27^x=V3

(3^3)^x=3^1/2

3^3x=3^1/2

3x=1/2

x=1/2:3

x=1/2.1/3

x=1/6

5^(5x-4)=(1/5)^(x+1)

5^(5x-4)=(5^-1)^(x+1)

5^(5x-4)=5^-1.(x+1)

5^(5x-4)=5^(-x-1)

5x-4=-x-1

5x+x=-1+4

6x=3

x=3/6 (simplifica por 3)

x=1/2