Question

Sendo S=(x+√7)•(x-√7), P=(x-3)²-12 e Q=(x+5)(x-2)(x-1), determine Q-(S+P).

Answer 1

$s = (x + \sqrt{7} ).(x - \sqrt{7} ) \\ p = (x - 3)^{2} - 12 \\ q = (x + 5).(x - 2).(x - 1)$
Q-(S+P)

(x+5).(x-2).(x-1)-[ (x+\/7).(x-\/7)+(x-3)^3-12)=>

(x^2-7x+10)(x-1)-(x^2-19+x^3-9x^2+27x-27)=>
x^3-x^2-7x^2+7x+10x-10-(-8x^2-46+x^3+27x)=>

x^3-x^2-7x^2+7x+10x-10+8x^2+46-x^3-27x=>

-10x+36----->Essa é a resposta