Question

sendo r//s//t, a e b transversais, determine o valor de x​

Answer 1

Resposta:

$\sf \dfrac{x + 1}{4} = \dfrac{2x - 6}{6} \\\\4(2x - 6) = 6(x + 1)\\8x - 24 = 6x + 6 \\8x - 6x = 6 + 24\\2x = 30 \\\\x = \dfrac{30}{2} \\\\x = 15$

Explicação passo-a-passo:

Usar o teorema de Tales: