Question

sendo P(x)=2x^4 -x³+x²+x+3 e Q(x)=x³+2x²-x+3,calcular: P(X) + Q(X)
Q (x)- P (x)
P (X)-Q (x)

Answer 1

P(x)+Q(x)

2x⁴-x³+x²+x+3 +(x³+2x²-x+3)=

2x⁴-x³+x³+x²+2x²+x-x+3+3=

2x⁴+3x²+6




Q(x) -P(x)


x³+2x²-x+3 - (2x⁴-x³+x²+x+3)=

x³+2x²-x+3-2x⁴+x³-x²-x-3=

-2x⁴+x³+x³+2x²-x²-x-x+3-3=

-2x⁴+2x³+x²-2x

P(x) - Q(x)

2x⁴-x³+x²+x+3 -(x³+2x²-x+3)=

2x⁴-x³+x²+x+3-x³-2x²+x-3=

2x⁴-x³-x³+x²-2x²+x+x+3-3=

2x⁴-2x³+1x²+2x