Question

Sendo o valor de cos x = 3/5, ache o valor de sen x, e posteriormente, ache o valor de tg x

Answer 1

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cosx=3/5

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senx^2+cosx^2=1

senx^2=1-cosx^2

senx^2=1-(3/5)^2

senx^2=1-9/25

senx^2=25-9/25

senx^2=16/25

senx=√16/25

_________|

senx=4/5
_________|

tgx=senx/cosx


tgx=4/5÷3/5

tgx=4/5×5/3

tgx=20/15
__________|
tgx=4/3

espero ter ajudado!

bom dia !