Question

sendo logx^3 + logx^5 + logx^10 = -126, qual o valor de x?

Answer 1

$\log x^3+\log x^5+\log x^{10}=-126\\ \\\log (x^3\cdot x^5\cdot x^{10})=-126\\ \\\log x^{18}=-126\\ \\18\cdot\log x=-126\\ \\\log x=-\frac{126}{18}\\ \\\log x=-7\\ \\x=10^{-7}$