Question

Sendo log2=a e log3=b, determine:
a)log81/raiz de 9
b)log64/27

Answer 1

$a)\log \frac{81}{ \sqrt{9} }=\log \frac{ 3^{4} }{3}=\log 3^{3}=3.\log3=3b$
$b)\log \frac{64}{27}=\log \frac{ 2^{6} }{ 3^{3} }=\log 2^{6}-\log 3^{3}=6.\log2-3.\log3=6a-3b$