Question

Sendo log2 =a e log3=b calcule log72
2

Answer 1

quando nao aparece a base no  log e pq a base é 10 ,mas calcular sem a base 10:
    
  log72 =log72              
             log10 na base 10=1
log72=log8·9=
log2³+log3²=
3log2+2log3=
3a+3b
                                     

Answer 2

$log2=a \\ log3=b$


$\frac{log72}{2} = \\ \\ \frac{log(2.2.2.3.3)}{2}= \\ \\ \frac{log2+log2+log2+log3+log3}{2}= \\ \\ \frac{a+a+a+b+b}{2}= \\ \\ \frac{3a+2b}{2}=1,5a+b \\ \\ \\ \frac{log72}{2}=1,5a+b$