Question

Sendo log2=a e log3=b, calcule: log2,5 e log da raiz de 3 na base 10

Answer 1

$a)log(2,5)= \\ \\ log( \frac{10}{4})= \\ \\ log( \frac{10}{2*2} )= \\ \\ log(10)-log(2)-log(2)= \\ \\ 1-a-a=1-2a$


$b)log_{10}\sqrt3= \\ \\ log_{10}3^{ \frac{1}{2}}= \\ \\ \frac{1}{2}*log_{10}3= \\ \\ \frac{1}{2}*b= \frac{b}{2}$