sendo log2=a e log3=b calcule
A) log81/√3
B) log(8×√27)
C) log180
Soluções para a tarefa
Respondido por
2
sendo log 2=a e log 3=b calcule
A) log 81/√3
=log 3⁴- log√3
=log 3⁴- log 3^(1/2)
=4 * log 3 - (1/2) * log 3
=4 * b -(1/2)* b
= (7/2) * b
B) log (8×√27) = log 8 + log √27
=log 2³ + log 3^(3/2)
= 3 * log 2 +(3/2) * log 3
= 3 * a +(3/2) * b
C) log 180 = log 3² * 2² * 5
= 2 * log 3 + 2 * log 2 + log 5
= 2 * log 3 + 2 * log 2 + log 10/2
= 2 * log 3 + 2 * log 2 + log 10 - log 2
= 2 * log 3 + log 2 + 1
= 2b+ a+1
Perguntas interessantes