Question

sendo log2=0,301, o número log5^20 é?

Answer 1

Olá!

$\log 5^{20}  = \\\\ 20 \cdot \log 5 = \\\\ 20 \cdot \log (\frac{10}{2}) = \\\\ 20 \cdot (\log 10 - \log 2) = \\\\ 20(1 - 0,301) = \\\\ 20 \cdot 0,699 = \\\\ \boxed{13,98}$