Question

Sendo Log2= 0,301 é Log3= 0,477; calcule:
a) log 72
b) log 14
c) log 32

Answer 1

Olá,

a)
$log(72) \\ log( {2}^{3} \times {3}^{2} ) \\ log( {2}^{3} ) + log( {3}^{2} ) \\ 3 \times log(2) + 2 \times log(3) \\ 3 \times 0.301 + 2\times 0.477 \\ 0.903 + 0.954 \\ 1.857$


b)
$log(14) \\ log(2 \times 7) \\ log(2 ) + log(7) \\ 0.301 + 0.845 \\ 1.146$


c)
$log(32) \\ log( {2}^{5} ) \\ 5 \times log(2) \\ 5 \times 0.301 \\ 1.505$