sendo log2 = 0.30 e log 3 = 0.47 então log 6 raiz 2/5? gostaria de saber, por favor.
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Boa noite!
![\log 6\sqrt{\dfrac{2}{5}}=\log 6+\log\sqrt{\dfrac{2}{5}}\\\log\left(2\cdot 3\right)+\log\left(\dfrac{2}{5}\right)^{\dfrac{1}{2}}\\\log 2+\log 3+\dfrac{1}{2}\cdot\log\left(\dfrac{2}{5}\right)\\\log 2+\log 3+\dfrac{1}{2}\cdot\left(\log 2-\log 5\right)\\\log 2+\log 3+\dfrac{1}{2}\cdot\left[\log 2-\log\left(\dfrac{10}{2}\right)\right]\\\log 2+\log 3+\dfrac{1}{2}\cdot\left(\log 2-\log 10+\log 2\right)\\0,30+0,47+0,5\cdot(0,3-1+0,3)=0,57](https://tex.z-dn.net/?f=%5Clog+6%5Csqrt%7B%5Cdfrac%7B2%7D%7B5%7D%7D%3D%5Clog+6%2B%5Clog%5Csqrt%7B%5Cdfrac%7B2%7D%7B5%7D%7D%5C%5C%5Clog%5Cleft%282%5Ccdot+3%5Cright%29%2B%5Clog%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E%7B%5Cdfrac%7B1%7D%7B2%7D%7D%5C%5C%5Clog+2%2B%5Clog+3%2B%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%5Clog%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5C%5C%5Clog+2%2B%5Clog+3%2B%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%5Cleft%28%5Clog+2-%5Clog+5%5Cright%29%5C%5C%5Clog+2%2B%5Clog+3%2B%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%5Cleft%5B%5Clog+2-%5Clog%5Cleft%28%5Cdfrac%7B10%7D%7B2%7D%5Cright%29%5Cright%5D%5C%5C%5Clog+2%2B%5Clog+3%2B%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%5Cleft%28%5Clog+2-%5Clog+10%2B%5Clog+2%5Cright%29%5C%5C0%2C30%2B0%2C47%2B0%2C5%5Ccdot%280%2C3-1%2B0%2C3%29%3D0%2C57 "\log 6\sqrt{\dfrac{2}{5}}=\log 6+\log\sqrt{\dfrac{2}{5}}\\\log\left(2\cdot 3\right)+\log\left(\dfrac{2}{5}\right)^{\dfrac{1}{2}}\\\log 2+\log 3+\dfrac{1}{2}\cdot\log\left(\dfrac{2}{5}\right)\\\log 2+\log 3+\dfrac{1}{2}\cdot\left(\log 2-\log 5\right)\\\log 2+\log 3+\dfrac{1}{2}\cdot\left[\log 2-\log\left(\dfrac{10}{2}\right)\right]\\\log 2+\log 3+\dfrac{1}{2}\cdot\left(\log 2-\log 10+\log 2\right)\\0,30+0,47+0,5\cdot(0,3-1+0,3)=0,57")
Espero ter ajudado!
Espero ter ajudado!
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