Question

Sendo log2 = 0,3; log3= 0,4 e log5= 0,7 , calcule log(base8)600

Answer 1

$log[8]600 = \frac{log600}{log8} = \frac{log(2*3*10^{2} )}{log2^{3} } = \frac{log2+log3+2log10 }{3log2} =$
$=\frac{0,3+0,4+2(1)}{3*0,3} = \frac{2,7}{0,9} =3$