Question

Sendo log X +log x^2 + log x^3+ log x^4=-20

Answer 1

 acho q é isso
 logx + logx² + logx³ + logx^4 = -20 
log (x*x²*x³*x^4) = -20 ---> loga+logb = log(a*b) 
log x^10 = -20 
10log x = -20 ---> log(a^n) = n*loga 
log x = -2 
10^-2 = x 
x = 0.01, letra d

Answer 2

logx + logx² + logx³ + logx^4 = -20 
log (x*x²*x³*x^4) = -20 ---> loga+logb = log(a*b) 
log x^10 = -20 
10log x = -20 ---> log(a^n) = n*loga 
log x = -2 
10^-2 = x 
x = 0.01, letra d