Question

Sendo log x = 4 e log y² = 7, qual o valor log x³ + 2.log x +2.log y?

Answer 1

log(y^2)= 7 usamos a regra do tombo
2log(y)=7
log(x^3)+2log(x)+2log(y)=
3log(x) +2.4+7
3.4+8+7
12+15
27