Question

Sendo log aA=1, log aB=2 e log aC=3 calcule

A) log a(a.b.c)

B) log a(a:b)

Answer 1

A) log a(a.b.c) 

= log a A + log a B + log a C

= 1 + 2 + 3

= 6

B) log a(a/b)

= log a A - log a B

= 1 - 2

= - 1