Question

Sendo log 3 = 0,47 , log 5 = 0,69 e usando a propriedade log a (b.c) = log a b+log a b+ log a c, calcule log 15

Answer 1

log15 = log(3)(5) = log 3 + log 5 = 0,47 + 0,69 = 1,16

Answer 2

log 15= log (3.5) = log 3+ log 5
0,47+ 0,69 =
1,16

Portanto, log15= 1,16