Question

Sendo log 2 = a, log 3 = b, calcule:

log(6. 4√12)

URGENTE!!!!!!!!!!!!1

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\mathsf{log(6.4\sqrt{12})}$

$\mathsf{log((2.3).(2.2).(12^\frac{1}{2}))}$

$\mathsf{log((2.3).(2.2).(3.2.2)^\frac{1}{2})}$

$\mathsf{log\:2 + log\:3 + log\:2 + log\:2 + \dfrac{1}{2}(log 3 + log\:2 + log\: 2)}$

$\mathsf{a + b + a + a + \dfrac{1}{2}(b + a + a)}$

$\mathsf{3a + b + \dfrac{1}{2}(2a + b)}$

$\mathsf{\dfrac{6a + 2b + 2a + b}{2}}$

$\boxed{\boxed{\mathsf{\dfrac{8a + 3b}{2}}}}$

Answer 2

Resposta:

log(6. 4√12)

log  6 + log 4 + log √12

log  6 + log 4 +(1/2) *  log 12

log  2+log 3 +2 log 2 +(1/2) *  ( 2*log 2+ log 3)

a+b+2*a+(1/2)*(2*a+b)

=3a+b+a+b/2

=4a+3b/2