Question

sendo log 2= a e log 3=b, calcule log 6 log 24 log 300 me ajudem por favor

Answer 1

log 6 = (2.3)

log 6 = log 2 + log 3

log 6 = a + b

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log 24 = (2.2.2.3)

log 24 = log 2 + log 2 + log 2 + log3

log 24 = a + a + a + b

log 24 = 3a + b

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log 300 = (3.10²)

log 300 = log 3 + log10²

log 300 = log 3 + 2 log10

log 10 na base 10 = 1

log 300 = b + 2.1

log 300 = b + 2

Espero ter ajudado!