Question

Sendo log 2= a e log 3= b, calcule : log 150

Answer 1

(a)
log 54 =>
log 27 * 2 =>
log 27 + log 2 =>
log 3^3 + a =>
3 * log 3 + a =>
==========
3b + a
==========

(b)
log 150 =>
log 300/2 =>
log 300 - log 2 =>
log 3 * 100 - a =>
log 3 + log 100 - a =>
===================
b + 2 - a
===================

(c)

log 2,56 =>
log 256/100 =>
log 256 - log 100 =>
log 2^8 - 2 =>
8 log 2 - 2 =>
8a - 2 =>
==================
2(4a - 1)
============