Question

Sendo log 2=0,301, log 3=0,477 e log 5=0,698, então log 450 será igual a?

Answer 1

$\log450=\\\\\log(3^2\cdot5\cdot10)=\\\\\log3^2+\log5+\log10=\\\\2\cdot\log3+0,698+1=\\\\2\cdot(0,477)+1,698=\\\\0,954+1,698=\\\\\boxed{2,652}$