Question

sendo log 2 = 0,30 , log 3 = 0,48 e log 7 = 0,85 determine:

Log 196

Log 72

Answer 1

196/2= 98/2= 49/7=7/7=1
Entao 196= 2^2*7^2
Portanto log196=log2^2+log7^2=2*log2+ 2*log7
=0,6+1,7= 2,3.

72/2=36/2=18/2=9/3=3/3=1
Então 72= 2^3*3^2
Portanto log72= log2^3+log3^2= 3*log2+2*log3
=0,9+0,96=1,86