Question

Sendo log 2 = 0,3; log3 = 0,5, calcule: log(600)

Answer 1

log(600) =
log(2³ x 5² x 3) =
log(2³) + log(5²) + log(3) =
3log(2) + 2log(5) + log(3) =
3log(2) + 2log(10/2) + log(3) =
3log(2) + 2[log(10) - log(2)] + log(3) =
3log(2) + 2[1 - log(2)] + log(3) =
3log(2) + 2 - 2log(2) + log(3) 

Substituindo os valores
3(0,3) + 2 - 2(0,3) + 0,5 = 2.8

log(600) = 2.8