Question

Sendo log 2=0,3 ; log 3=0,4. Determine: log 36+ log 12

Answer 1

Resposta:

$log(36) + log(12) = \\ log(6 \times 6) + log(4 \times 3) = \\ log(6) + log(6) + log(4) + log(3) = \\ log(2 \times 3) + log(2 \times 3) + log( {2}^{2} ) + 0.4 = \\ log(2) + log(3) + log(2) + log(3) + 2 log(2) + 0.4 = \\ 0.3 + 0.4 + 0.3 + 0.4 + 2(0.3) + 0.4 = \\ 0.6 + 0.8 + 0.6 + 0.4 = 2.4$