Question

Sendo log 2 = 0,3 e log 3 = 0,48, calcule:

a) Log 16

b) Log 1,2

c) Log 0,9

d) Log 54

e) Log 1,8

f) Log (base 12) 27

g) Log (base 6) 12

Answer 1

A) Log16 m.m.c de 16 = 2.2.2.2 0,3+0,3+0,3+0,3 = 1,2 B)Log1,2 = log (6/5)= log6 - log5= 0,079 C) log 0,9 = log (9/10) = log9 - log10 =0,045 D) log54 m.m.c 54 = 2.3.3.3= 0.3+0.47+0.47+0.47 = 1,7 E) log1,8 = log (9/5) = log9-log5 =0,25 F) 1,38 G) 1,32 Espero ter ajudado