Question

Sendo f(x)=x²-5x+6, determine. f(0) e f(4). Os valores de x para f(x)=0

Answer 1

f(x)= x²-5x+6
f(0)= 0²-5.0+6
f(0)= +6

f(4)= 4²-5.4+6
f(4)= 16 -20+6
f(4)= -4 +6
f(4)= +2

x²-5x+6=0
∆= (-5)²-4.1.6
∆= 25 -24
∆= 1
x= -(-5)±√1/2.1
x= 5±1/2
x1= 5+1/2= 6/2=3
x2= 5-1/2= 4/2=2