Question

Sendo f(x)=x²+3x-2 calcule: f(1/2)

Answer 1

f(x)=x²+3x-2

$f( \frac{1}{2} )=( \frac{1}{2}) ^{2} +3( \frac{1}{2} )-2$

$f( \frac{1}{2})= \frac{1}{4} + \frac{3}{2} -2$

$f( \frac{1}{2} )= \frac{1+6-8}{4}$

$f( \frac{1}{2})=- \frac{1}{4}$

Answer 2

Olá, Gabrielle !

$f(x)=x^2+3x-2$

Se $x=\dfrac{1}{2}$, temos:

$f(\frac{1}{2})=\left(\dfrac{1}{2}\right)^2+3\cdot\dfrac{1}{2}-2$

$f(\frac{1}{2})=\dfrac{1}{4}+\dfrac{3}{2}-2$

Veja que, $\text{mmc}(4,2,1)=4$, logo:

$f(\frac{1}{2})=\dfrac{1+6-8}{4}=\dfrac{-1}{4}$.

Espero ter ajudado, até mais ^^