Question

Sendo F(x)=a.x+b,determine a lei que define a função,sendo F(-3)=-8 e F(2)=7

Answer 1

$\left \{ {{-3=-8a + b} \atop {2 =7a + b}} \right. .(-1)= \left \{ {{3= 8a -b} \atop {2=7a + b}} \right. + \\\\ 15a = 5 \\a = 5/15\\\\a=1/3\\\\7a + b = 2\\7. \frac{1}{3} + b = 2\\\\ \frac{3b + 7}{3} = 2\\ 3b +7 = 6\\3b = -1\\\\b = -\frac{1}{3} \\\\ f(x) = \frac{x}{3} - \frac{1}{3} \\ou \\ f(x) = \frac{x-1}{3}$