Sendo f(x) = 4x + 2, determine:
A) f(-1) + f(0) + f(3)
B) f(0) - f(-1) + f(2)
C) f(1) + f(3)
f(2)
D) f(4) + f(-2) - f(5)
f(2)
Soluções para a tarefa
A) 4.(-1)+2= -2
4.(0)+2= 2
4.(3)+2= 14
2+2+14= 18
B) 4.(0)+2= 2
4.(-1)+2= -2
4.(2)+2= 10
2-(-2)+10= 14
C) 4.(1)+2= 6
4.(3)+2= 14
4.(2)+2= 10
(6+14)/10= 2
D) 4.(4)+2= 18
4.(-2)+2= -6
4.(5)+2= 22
4.(2)+2= 10
[18+(-6)-22]/10= -1
f(x) = 4x + 2
A) f(-1) + f(0) + f(3) = - 6 +2 14 = 10
f(-1) = 4.(-1) +2 = - 4 +2=-2
f(0)= 4.0 +2= 0+2=2
f(3) = 4.3 +2=12+2=14
f(2) = 4.2+2= 8+2=10
f(1)=4.1+2=4+2=6
f(4)=4.4+2=16+2=18
f(5)=4.5+2=20+2=22
B) f(0) - f(-1) + f(2) = 2-(-2)+10=2+2+10=14
C) f(1) + f(3) =
f(2)
6+14 = 20/10 =2
10
D) f(4) + f(-2) - f(5) = 18 +10 - 22 = 6
f(2) 10 10