Question

sendo f(X) = 4x+2,calcule: f(-1),f(0),f(3)

Answer 1

f(x) = 4x + 2

f(- 1) = 4 (- 1) + 2 
= - 4 + 2
= - 2

f(0) = 4 * 0 + 2
= 0 + 2
= 2

f(3) = 4 * 3 + 2
= 12 + 2
= 14

Answer 2

f(x)= 4x+2
f(-1)= 4.(-1)+2
f(-1)= -4+2
f(-1)= -2

f(x)= 4x+2
f(0)= 4.(0)+2
f(0)= 0+2
f(0)= 2

f(x)= 4x+2
f(3)= 4.(3)+2
f(3)= 12+2
f(3)= 14