Question

Sendo f(x)= 2x²-3x+1, calcule:
a) f (raiz de dois/3)

Answer 1

$a) \: f( \frac{ \sqrt{2} }{3} ) = 2 {( \frac{ \sqrt{2} }{3} )}^{2} -3 ( \frac{ \sqrt{2} }{3} ) + 1 = \\ = 2 \times \frac{2}{9} - \sqrt{2} + 1 = \\ = \frac{4}{9} - \sqrt{2} + 1 =\\ = \frac{4}{9} + \frac{9}{9} - \sqrt{2} = \\ = \frac{13}{9} - \sqrt{2}$