Question

sendo f(x)=-2x²+3x-1,calcule:A)f(-2). B)f(-1) C)f(0) D)f(2) E)f(3/2) F)f(1/2)

Answer 1

Oi Ana

f(x) = -2x² + 3x - 1

a) f(-2) = -2*(-2)² + 3*(-2) - 1 = -8 - 6 - 1 = -15 

b) f(-1) = -2*(-1)² + 3*(-1) - 1 = -2 - 3 - 1 = -6

c) f(2) = -2*2² + 3*2 - 1 = -8 + 6 - 1 = -3

d) f(3/2) = -2*(3/2)² + 3*3/2 - 1 = -9/2 + 9/2 - 1 = -1

e) f(1/2) = -2*(1/2)² + 3*(1/2) - 1 = -2/4 + 3/2 - 1 = 0

.