Question

Sendo f(x)=2x²-3x+1 calcule:

A. f(0)
B. f(1)
C. f(2)
D. f(3)

Answer 1

a) f(0) = 2.(0)^2 - 3.0 + 1 = 1
b) f(1) = 2.(1)^2 - 3.1 + 1 = 2 - 3 + 1 = 0
c) f(2) = 2.(2)^2 - 3.2 + 1 = 8 - 6 + 1 = 3
d) f(3) = 2.(3)^2 - 3.3 + 1 = 18 - 9 + 1 = 10

Espero ter ajudado!

Answer 2

Explicação passo-a-passo:

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Temos a seguinte função:

$\boxed{f(x)=2x^{2} -3x+1}$

a)Calculando $f(0)$ :

$f(0)=2.0^{2} -3.0+1\\\\f(0)=0-0+1\\\\\boxed{\boxed{f(0)=1}}$

b)Calculando $f(1)$ :

$f(1)=2.1^{2} -3.1+1\\\\f(1)=2.1-3+1\\\\f(1)=2-3+1\\\\\boxed{\boxed{f(1)=0}}$

c)Calculando $f(2)$ :

$f(2)=2.2^{2} -3.2+1\\\\f(2)=2.4-6+1\\\\f(2)=8-6+1\\\\\boxed{\boxed{f(2)=3}}$

d)Calculando $f(3)$ :

$f(3)=2.3^{2} -3.3+1\\\\f(3)=2.9-9+1\\\\f(3)=18-9+1\\\\\boxed{\boxed{f(3)=10}}$