sendo f(x) 2x -3x +1, calcule 2/3
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f(2/3) = 2.2/3 -3.2/3 +1
f(2/3) = 4/3-6/3+3.1/3
f(2/3) = 4/3+3/3 -6/3
f(2/3) = 7/3-6/3
f(2/3) = 1/3
f(2/3) = 4/3-6/3+3.1/3
f(2/3) = 4/3+3/3 -6/3
f(2/3) = 7/3-6/3
f(2/3) = 1/3
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