Question

sendo f(x) = 2 +cosx e g(x)=sen2x, X pertecente R, dertemine f(pi/3) + g(pi/2)

Answer 1

f(x) = 2 + cosx   ⇔   f(π/3) = 2 + cos(π/3)   ⇔   f(π/3) = 2 + (1 / 2) = 5 / 2

g(x) = sen(2x)   ⇔   g(π/2) = sen[2 * (π/2)]   ⇔   g(π/2) = sen(π) = 0

Logo,

f(π/3) + g(π/2) = (5 / 2) + 0 = 5 / 2