Question

Sendo f(x+1)=2.f(x)+5 onde f(0)=6, determine f(2)

Answer 1

f[x+1] = 2.f[x] + 5

f[0] = 6

f[0+1] = 2.f[0] + 5

f[1] = 2.6 + 5

f[1] = 12 + 5

f[1] = 17

f[1+1] = 2.f[1] + 5

f[2] = 2.f[1] + 5

f[2] = 2.17 + 5

f[2] = 34 + 5

f[2] = 39