Question

Sendo DE paralela a BC, qual a medida de AB?
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Answer 1

Resposta:

$\dfrac{x}{x+3} = \dfrac{10}{15}$

15x = 10*(x  + 3)

15x = 10x + 30

15x - 10x = 30

5x = 30

x  = 30/5

x = 6

AB = AD + DB

AB = x + x + 3

AB = 6 + 6 + 3

AB = 15