Question

sendo cos x = - 4/5 e tg x < 0 , calcule o valor da expressão 2 cot g x / 1 + tg² x

Answer 1

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Answer 2

cotgx=-4/3 tgx^2=9/16cosx=-4/5 tgx<0 Cotgx+tg^2x
(tgx)^2= senx/cosx^2=senx^2/cosx^2
cotgx=1/tgx=1/senx/cosx=cosx/senx
cosx^2+senx^2=1
senx^2=1-cos^2=1-(-4/5)^2
senx^2=1-16/25=25-16/25=9/25
senx^2/cosx^2=9/25/16/25=9/25.25/16=9/16
senx^2=9/25 senx=+ou- 3/5
tgx<0 = senx/cosx<0 =senx/-4/5<0= -senx.5/4<0=senx.(5/4)>0=
senx>0

senx=3/4=cotgx=-4/5.5/3=

-4/3+9/16/2=-64=27/48=-37/48
=9/25/16/25=
9/16