Question

Sendo A= (x-1)²+3x-x² e B=-[(x+1)²-x(3+x)] calcule A.B

Answer 1

A=(x-1)²+3x-x² e B=-[(x+1)²-x(3+x)]
A=$x^{2}$-2x+1+3x-$x^{2}$
A=x+1
B=-[$x^{2}$+2x+1-3x-$x^{2}$]
B=x-1

AB=$x^{2}$ -1