Question

sendo a p.a, onde a1 =4,(r=6)obtenha o 502° termo

Answer 1

$a_1 =4 \\ r = 6 \\ a_{502} = \,? \\ \\ a_n = a_1 + (n-1)r \\ \\ a_{502} = 4 + (502-1)6 \\ \\ a_{502} = 4 + 501.6 \\ \\ a_{502} = 4 + 3006 \\ \\ a_{502} = 3010$