Sendo a matriz B= (bij) 5x6, qual o valor numérico do elemento (bij) 4x3, sendo que 7i + 8j2:
Soluções para a tarefa
Resposta:
B = b11 b12 b13 b14 b15 b16
b21 b22 b23 b24 b25 b26
b31 b32 b33 b33 b35 b36
b41 b42 b43 b44 b45 b46
b51 b52 b53 b54 b55 b56
b11 = 7.1+8.1.2
b11 = 7+16
b11 = 23
b12 = 7.1+8.2.2
b12 = 7+32
b12 = 39
b13 = 7.1+8.3.2
b13 = 7+48
b13 = 55
b14 = 7.1+8.4.2
b14 = 7+64
b14 = 71
b15 = 7.1+8.5.2
b15 = 7+80
b15 = 87
b16 = 7.1+8.6.2
b16 = 7+96
b16 = 103
b21 = 7.2+8.1.2
b21 = 14+16
b21 = 30
b22 = 7.2+8.2.2
b22 = 14+32
b22 = 46
b23 = 7.2+8.3.2
b23 = 14+48
b23 = 62
b24 = 7.2+8.4.2
b24 = 14+64
b24 = 78
b25 = 7.2+8.5.2
b25 = 14+80
b25 = 94
b26 = 7.2+8.6.2
b26 = 14+96
b26 = 110
b31 = 7.3+8.1.2
b31 = 21+16
b31 = 37
b32 = 7.3+8.2.2
b32 = 21+32
b32 = 53
b33 = 7.3+8.3.2
b33 = 21+48
b33 = 69
b34 = 7.3+8.4.2
b34 = 21+64
b34 = 85
b35 = 7.3+8.5.2
b35 = 21+80
b35 = 101
b36 = 7.3+8.6.2
b36 = 21+96
b36 = 117
b41 = 7.4+8.1.2
b41 = 28+16
b41 = 44
b42 = 7.4+8.2.2
b42 = 28+32
b42 = 60
b43 = 7.4+8.3.2
b43 = 28+48
b43 = 76
b44 = 7.4+8.4.2
b44 = 28+64
b44 = 92
b45 = 7.4+8.5.2
b45 = 28+80
b45 = 108
b46 = 7.4+8.6.2
b46 = 28+96
b46 = 124
b51 = 7.5+8.1.2
b51 = 35+16
b51 = 51
b52 = 7.5+8.2.2
b52 = 35+32
b52 = 67
b53 = 7.5+8.3.2
b53 = 35+48
b53 = 83
b54 = 7.5+8.4.2
b54 = 35+64
b54 = 99
b55 = 7.5+8.5.2
b55 = 35+80
b55 = 115
b56 = 7.5+8.6.2
b56 = 35+96
b56 = 131
B = 23 39 55 71 87 103
30 46 62 78 94 110
37 53 69 85 107 117
44 40 76 92 108 124
51 67 83 99 115 131