Question

Sendo ⁿ a maior raiz da equação 2²^x–8.2^x+12=0, determine o valor de 4ⁿ

Answer 1

Resposta:

2^2x-8.2^x+12=0  Para 2^x= Y

(2^x)²-8.2^x+12=0

y²-8y+12=0

Delt=-8²-4.1.12

Delt= 64-48

Delt=16

Y=[-(-8)+-√16]/2.1

Y=8+-4/2

Y'=8+4/2 = 12/2 = 6

Y''=8-4/2 = 4/2= 2

2^x=Y

2^x=6

Log2^x=Log6

xlog2=Log6

x=Log6/Log2

4^N=?

4^(Log2.Log3/Log2)

4^(Log2+Log3/Log2)